爱情公寓5全集下载:2002*(1-1/3)*(1-1/4)*(1-1/5)*.....*(1-1/2002)=?
来源:百度文库 编辑:杭州交通信息网 时间:2024/05/11 05:54:21
=2002*[2/3*3/4*...*2001/2002]
=2002*(2/2002)
=2
看到题后不要慌,如果没思路,就把式子动一动,
动几下发现规律就迎刃而解了.
2
中间可以化间啊
得 2 啊!!
2002*(1-1/3)*(1-1/4)*(1-1/5)*.....*(1-1/2002)
=2002*(2/3)*(3/4)*(4/5)*.....*(2000/2001))*(2001/2002)
=2
2002*(1-1/3)*(1-1/4)*(1-1/5)*.....*(1-1/2002)=?
计算(1/2+1/3+......+1/2002)(1+1/2+1/3+......+1/2001)-(1+1/2+......+1/2002)(1/2+1/3+....+1/2001)
求(1-1/2+1/3-1/4+...+1/1999)/(1/2000+1/2002+1/2004+...+1/3998)
1/(1*2)+1/(2*3)+1/(3*4)+......+1/(2002*2003)=/
1/(1*2)+1/(2*3)+1/(3*4)+1/(4*5 )+...+1/(2000*2001)+1/(2001*2002)=
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
计算:(1/2004-1)(1/2003-1)(1/2002-1)'''(1/2-1)
1/1×2+1/2×3+1/3×4+1/4×5+1/5×6……+1/2002×2003+1/2003×2004
计算1+2+3+...+2002+2003+2002+...+3+2+1
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)