北京橡胶研究院家属院:一道数学 不是应用题 很急用

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去括号,合并同类项
(x^3-3x^2y+3xy^2)-(x^3-3x^2y-3xy^2-y^3)
(要过程)

(x^3-3x^2y+3xy^2)-(x^3-3x^2y-3xy^2-y^3)
=x^3-3x^2y+3xy^2-x^3+3x^2y+3xy^2+y^3
=(x^3-x^3)+(-3x^2y+3x^2y)+(3+3)xy^2+y^3
=6xy^2+y^3

我是教授

(x^3-3x^2y+3xy^2)-(x^3-3x^2y-3xy^2-y^3)
=x^3-3x^2y+3xy^2-x^3+3x^2y+3xy^2+y^3
=(x^3-x^3)+(-3x^2y+3x^2y)+(3+3)xy^2+y^3
=6xy^2+y^3

我是学生!

解:(x^3-3x^2y+3xy^2)-(x^3-3x^2y-3xy^2-y^3)
=x^3-3x^2y+3xy^2-x^3+3x^2y+3xy^2+y^3
=(1-1)x^3+(-3+3)x^2y+(3+3)xy^2+y^3
=6xy^2+y^3

(x^-3x^2y+3xy^2)-(x^3-3x^2y-y^3)
=x^3-3x^2y-x^3+3xy^2+y^2+y^3
=(1-1) x^3+(-3+3)x^2y+(3+3)xy^2+y^3
=6xy^2+y^3

=3x^-6x^y+6xy^-3x^+6x^y+6xy^+3y
=3y^+12xy^
仅供参考