通便排毒的水果有哪些:在三角形ABC中,a,b,c分别是角A,B,C的对边,设a+c=2b,A-C=60度,求sinB的值

来源:百度文库 编辑:杭州交通信息网 时间:2024/04/29 22:07:45

楼上的算的太复杂了,看了半天没看出答案

a+c=2b =>sinA+sinC=2sinB=2SIN(B/2)COS(B/2)

sinA+sinC=2sin((A+C)/2)COS((A-C)/2) =>2COS(B/2)COS((A-C)/2)

从而得出sin(B/2)=根号3/4 => COS(B/2)=根号13/4(排除是负数的可能)
sinB=SIN(B/2)COS(B/2)=根号39/8

楼上的错大了,a+c=2b能推出SIN(A+C)=SIN2B,应该是sinA+sinC=2sinB,靠
解:
因为a+c=2b,由正弦定理得,
sinA+sinC=2sinB=2sin(A+C)
因为A-C=60度
所以sin(C+60)+sinC=2sin(60+2C)
sinC*cos60+cosCsin60+sinC=2sin(60+2C)
3/2*sinC+根号3/2*cosC=4*sin(30+C)*cos(C+30)
根号3*(根号3/2*sinC+1/2*cosC)=4*sin(30+C)*cos(C+30)
根号3*sin(30+C)=4*sin(30+C)*cos(C+30)
得cos(C+30)=根号3/4
得sin(30+C)=根号13/4
得sin(60+2C)=2*根号3/4*根号13/4=根号39/8=sin(A+C)=sinB