如何自己选车牌号:函数F(X)=-SIN^2X+SINX+A,对任意X属于R有,1=<F(X)=<17/4,求实数A取值范围

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函数F(X)=-SIN^2X+SINX+A,对任意X属于R有,1=<F(X)=<17/4,求实数A取值范围?

思路`解法`

F(X)=-SIN^2X+SINX+A
=-(sinx-1/2)^2+A+1/4
因为:-1<=sinx<=1,所以-3/2<=sinx-1/2<=1/2,
-9/4<=-(sinx-1/2)^2<=0,
a-2<=f(x)<=a+1/4

又有:1=<F(X)=<17/4
则:
1<=a-2,
a+1/4<=17/4
解得
a>=3,
a<=4
实数A取值范围3<=A<=4.

F(X)=-SIN^2X+SINX+A
=-(ainx-1/2)^2+A+1/4
因为 -1≤sinx≤1
故: -3/2≤(sinx-1/2)≤1/2
0≤(sinx-1/2)^≤9/4
A-2 ≤ F(x)≤A+1/4
故:A-2≥1
A+1/4≤17/4
解得:3≤A≤4

F(X)=(sinX+1/2)^2+A-1/4

当sinX=1,F(X)有最大值2+A
当sinX=-1/2,F(X)有最小值A-1/4
∴A-1/4≤F(X)≤A+2
要条件成立,那么要
1≤A-1/4
A+2≤17/4
--->5/4≤A≤9/4