npc拉伊在哪:初二数学

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已知:根号下X+Y-3与根号下X-Y+5互为相反数,求X^2-Y^2的值

解:由题得:
(X+Y-3)^0.5 + (X-Y+3)^0.5 =0
且(X+Y-3)^0.5>=0 (X-Y+3)^0.5>=0
故只有当(X+Y-3)^0.5=0 (X-Y+3)^0.5=0时等式成立

则有方程组:X+Y-3=0
X-Y+5=0
解得:X+Y=3 X-Y=-5
X^2-Y^2=(X+Y)(X-Y)=-15

X+Y-3=0
X-Y+5=0故X=-1 Y=-4

X^2-Y^2=-15