圣餐仪式流程:已知3x-z=x+y+z=4x+2y-z,求x : y : z
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求求你,谢谢.
3x-z=x+y+z....(1)
3x-z=4x+2y-z...(2)
有(1)得y=2x-2z...(3)代入(2)
3x-z=4x+2(2x-2z)-z
3x-z=4x+4x-4z-z
4z=5x => x:z=4:5
=>x=5分之4z...代入(3)
y=5分之8z-2z => 5y=8z-10z => 5y=-2z => y:z=-2:5
所以 x:y:z=4:-2:5
把上面的等式构成两者方程,解方程可得
4:2:5
因为3x-z=4x+2y-z
两边加z得3x=4x+2y
0=x+2y
x=-2y
设y=a,则x=-2a
则原式为:-6a-z=-2a+a+z=-8a+2a-z
可得z=-5/2a
又x=-2a,y=a,z=-5/2a
所以x:y:z=-2:1:-5/2
通分得-4:2:-5
3x-z=x+y+z....(1)
3x-z=4x+2y-z...(2)
有(1)得y=2x-2z...(3)代入(2)
3x-z=4x+2(2x-2z)-z
3x-z=4x+4x-4z-z
4z=5x => x:z=4:5
=>x=5分之4z...代入(3)
y=5分之8z-2z => 5y=8z-10z => 5y=-2z => y:z=-2:5
所以 x:y:z=4:-2:5
经过代入验算正确
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