libjingle:高一对数题急需谢谢

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若log[a]b*log[3]a=5,求b

log[a]b=lgb/lga
-->log[a]b*log[3]a=5
= lgb/lga * lga/lg3
= lgb/lg3=5
lgb=5lg3
b=3^5

..............................lgb*lga
log[a]b*log[3]a=------------------------
..............................lga*lg3

...........................lgb
.................=------------------------=5
...........................lg3

lgb=5lg3=lg(3^5)
b=3^5=243

log[a]b=lnb/lna
log[3]a=lna/ln3
所以lnb/ln3=5
b=3的5次方