问道双线一区合区列表:(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)

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麻烦用简便算法，谢谢

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/2
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/2
=……
＝(3^64-1)/2

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
＝（3-1）(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)÷2
＝（3^2-1）(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)÷2
＝（3^4-1）(3^4+1)(3^8+1)(3^16+1)(3^32+1)÷2
=(3^8-1)(3^8+1)(3^16+1)(3^32+1)÷2
=(3^16-1)(3^16+1)(3^32+1)÷2
=(3^32-1)(3^32+1)÷2
=(3^64-1)/2

原式乘以(3-1)再除以2
原式=(3^64-1)/2=1716841910146256242328924544640

(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/(3-1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/2
=(3^4-1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)/2
……
=(3^64-1)/2

(3-1)*...

(3^64-1)/2

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1) 1 2 3 4 5=1 4,3,2,0,1,-3,() 数字推理 1, 1, 2, 2, 3, 4, 3, 5, ( ) 1,1,2,2,3,4,3,5,(?) 为什么？ 1 1 2 2 3 4 3 5 (?) 1,1,2,2,3,4,3,5,( ) 1/1*2+1/2*3+1/3*4+...+1/2000*2001 1/(1*2)+1/(2*3)+1/(3*4)+..+1/(99*100) 1*1/1*2+2*1/2*3+3*1/3*4+......+99*1/99*100