ajax异步刷新:有理数的巧算2

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1/3*1+1/4*2+1/5*3+...+1/1999*1997+1/2000*1998=?

原式=1/2*(1-1/3+1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7……+1/1995-1/1997+1/1996-1/1998+1/1997-1/1999+1/1998-1/2000)
=1/2*(1+1/2-1/1999-1/2000)
=1/2*(999/2000+1998/1999)
=1/2*(5993001/2000*1999)
=5993001/1999000

=0.5(1-1/3+1/2-1/4+1/3-1/5..........+1/1997-1/1999+1/1998-1/2000)=0.5(1+1/2-1/1999-1/2000)=(1999*3000-1999-2000)/(2*1999*2000)