重庆简图:若f(n)=(n+1)(n+2)(n+3)+……(n+n),求f(n+1)/f(n)
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f(n+1)=(n+1+1)(n+1+2)(.....(n+1+n+1)
=(n+2)(n+3)...(2n+1)(2n+2)
f(n)=(n+1)(n+2)(n+3)+……(n+n)
所以f(n+1)/f(n)=(2n+1)(2n+2)/(n+1)=2(2n+1)=4n+2
4n+2
若f(n)=(n+1)(n+2)(n+3)+……(n+n),求f(n+1)/f(n)
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