男皮风衣中长款:一些C/C++、VB的题，高分悬赏！~

1、若有说明语句：double *p,a; 则能通过scanf语句正确给输入项读入数据的程序段是
A) *p = &a; scanf (“%f”, p);
B) *p = &a; scanf(“%f”, p);
C) p = &a; scanf(“%f”, *p);
D) p = &a; scanf(“%f”, p);

2、要求通过while循环不断读入字符，当读入字母N时结束循环。若变量已经正确定以，以下正确的程序段是：
A) while ( (ch = getchar() ) != ‘N’) printf (“%c”,ch);
B) while ( ch = getchar() != ‘N’) printf (“%c”,ch);
C) while ( ch = getchar() == ‘N’) printf (“%c”,ch);
D) while ( (ch = getchar() ) == ‘N’) printf (“%c”,ch);

3、现有以下结构体说明和变量定义，如图所示，指针p、q、r分别指向链表中连续的三个节点。
struct node
{
char data;
struct node * next;
}*p,*q,*r;

现要将p和r所指节点交换前后位置，同时要保证链表的连续，以下不能完成此操作的语句是：
A) q->next = r->next; p->next = r; r->next = q;
B) p->next = r; q->next = r->next; r->next = q;
C) q->next = r->next; r->next = q; p->next = r;
D) r->next = q; p->next = r; q->next = r->next;

4、有如下程序：
#include <iostream.h>
using namespace std;

class Base
{
public:
void fun1 () { cout << “Base\n”;}
virtual void fun2 () { cout << “Base\n”;}
};
class Derived : public Base
{
public:
void fun1 () { cout << “Derived\n”;}
void fun2 () { cout << “Derived\n”;}
};
void f ( Base & b) {b.fun1(); b.fun2();}

int main()
{
Derived obj;
f(obj);
return 0;
}

执行这个程序的输出结果是
A) Base B) Base C) Derived D) Derived
Base Derived Base Derived