车间花槽图片:若tan(A+B)=2/5,tan(B-pai/4)=1/4,那么tan(A+pai/4)的值是多少.

来源:百度文库 编辑:杭州交通信息网 时间:2024/04/28 17:44:28

解:tan[A+(π/4)]=tan{(A+B)-[B-(π/4)]}
tan{(A+B)-[B-(π/4)]}
={tan{(A+B)-tan[B-(π/4)]}/{1+〈tan{(A+B)×tan[B-(π/4)]〉}
=[(2/5)-(1/4)]/[1+(2/5)×(1/4)]
=(3/20)/(22/20)
=3/22

解:tan[A+(π/4)]=tan{(A+B)-[B-(π/4)]}
tan{(A+B)-[B-(π/4)]}
={tan{(A+B)-tan[B-(π/4)]}/{1+〈tan{(A+B)×tan[B-(π/4)]〉}
=[(2/5)-(1/4)]/[1+(2/5)×(1/4)]
=(3/20)/(22/20)
=3/22