安佳奶粉银边和白边:⑧17. 已知：xyz=1 （5.8）

来源：百度文库 编辑：杭州交通信息网 时间：2024/05/03 16:40:22
⑧17. 已知：xyz=1 ,
求 x/(xy+x+1)+y/(yz+y+1)+z/(xz+z+1)
回答者：baiyuanyuand - 试用期 一级 3-25 13:44
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
这两部好像出问题了，有点怪怪的...

--------------------------------------------------------------------------------

原式=x/(xy+x+xyz)+y/(yz+y+1)+z/(xz+z+1)
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
=(yz+y+1)/(yz+y+1)

原式=x/(xy+x+xyz)+y/(yz+y+1)+z/(xz+z+1)
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
=(yz+y+1)/(yz+y+1)
=1

原式=x/(xy+x+xyz)+y/(yz+y+1)+z/(xz+z+1)
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
=(yz+y+1)/(yz+y+1)
=1

原式=x/(xy+x+xyz)+y/(yz+y+1)+z/(xz+z+1)
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
=(yz+y+1)/(yz+y+1)
=1

原式=x/(xy+x+xyz)+y/(yz+y+1)+z/(xz+z+1)
=1/(yz+y+1)+y/(yz+y+1)+yz/(xyz+yz+y)
=(1+y)/(yz+y+1)+yz/(yz+y+1)
=(yz+y+1)/(yz+y+1)

啊。萨

⑧17. 已知：xyz=1 （5.8） 题目是 :2005xyz xyz xyz xyz xyz201*xyz=9999的倍数 ,求xyz是多少,为什么(非IQ题) 已知实数x，y，z，且xyz不相等，x+y+z=11.4求x、y、z的值。 已知x+4y-3z=0,4x-5y+2z=0(xyz不等于0),则x:y:z=? 已知：x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z 已知4x-5y+2z=0,x+4y-3z=0 且xyz不等于0,求x:y:z的值。 正数x,y,z, xyz(x+y+z)=1,则(x+y)(x+z)最小值？ 已知1／x＋1／y＝1／6，1／y＋1／z＝1／9，1／z＋1／x＝1／15，求xyz／xy＋yz＋zx的值 已知3x-4y-z=0.2x+y-z=0,且xyz=0,求x+2y-3z/3x-2y+3z 请大家给我个算法:已知:s='(xyz)+*',t='(x+z)*y'.试用连接,求子串和置换等基本运算,将s化为t.谢谢帮忙!