无线电监督管理委员会:数学计算题

来源:百度文库 编辑:杭州交通信息网 时间:2024/05/10 07:57:34
1/(12×13)+1/(13×14)+……+1/(19×20)的值为:
A.1/12 B.1/20 C.1/30 D.1/40

此题运用了裂项求和法:1/n(n+1)=1/n-1/(n+1)
扩展:1/n(n+k)=1/k<1/n-1/(n+1)> (要记牢哦,高中很有用的)
所以 原式=1/12-1/13+1/13-1/14+……+1/19-1/20
=1/12-1/20=1/30 选C

1/(12×13)+1/(13×14)+……+1/(19×20)
=1/12-1/13+1/13-1/14+……+1/19-1/20
=1/12-1/20
=1/30
选C

原式
=(1/12-1/13)+(1/13-1/14)+……+(1/19-1/20)
=1/12-1/20=1/30
选C

1/(12×13)+1/(13×14)+……+1/(19×20)
=1/12-1/13+1/13-1/14+……+1/19-1/20
=1/12-1/20
=1/30
选C

1/(12×13)+1/(13×14)+……+1/(19×20)
=1/12-1/13+1/13-1/14+……+1/19-1/20
=1/12-1/20
=1/30
选C

1/(12×13)+1/(13×14)+……+1/(19×20)
=1/12-1/13+1/13-1/14+……+1/19-1/20
=1/12-1/20
=1/30
选C