上饶住房公积金提取:tan(3x/2)-tan(x/2)-2sinx/(cosx+cos(2x))=?
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tan(3x/2)-tan(x/2)-2sinx/(cosx+cos(2x))=?
tan(3x/2)-tan(x/2)-2sinx/(cosx+cos2x)
=sin(3x/2)/cos(3x/2)-sin(x/2)/cos(x/2)-2sinx/(cosx+cos2x)
=[sin(3x/2)cos(x/2)-cos(3x/2)sin(x/2)]/cos(3x/2)cos(x/2)-2sinx/(cosx+cos2x)
=2sin(3x/2-x/2)/[cos(3x/2+x/2)+cos(3x/2-x/2)]-2sinx/(cosx+cos2x)
=2sinx/(cos2x+cosx)-2sinx/[cosx+cos(2x)]
=0
tan 3x/2-tan x/2=2sin x /(cos x+cos 2x)
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tan(3x/2)-tan(x/2)-2sinx/(cosx+cos(2x))=?
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