高淳马拉松2017:大家帮帮忙,功率怎么算?
来源:百度文库 编辑:杭州交通信息网 时间:2024/05/31 18:52:07
3.35V,6毫安功率是多少瓦?
P=IU=6mA*3.35V=6*10(-3)*3.35V=2.01*10(-2)W
所以功率是2.01*10(-2)W,即0.0201W
0.0201w
P=UI
P=3.35*0.006=0.0201瓦
Honeydukes 正解
P=IU=6mA*3.35V=6*10(-3)*3.35V=2.01*10(-2)W
所以功率是2.01*10(-2)W,即0.0201W
0.0201w
P=UI
P=3.35*0.006=0.0201瓦
Honeydukes 正解