杭州交通信息网安卓运行exe游戏:八年级数学分式题.
来源：百度文库 编辑：杭州交通信息网 时间：2024/04/19 23:33:15
化简下列分式
(1)(x^2)/(x+y)-(x+y)/(x+y)
(2)2(a-3)/(a+3)(a-3)-3(a+3)/(a+3)(a-3)+(a+15)/(a+3)(a-3)
(3)1-(a+2)(a-2)/(a-2)(a-1)+(a-1)/(a-2)(a-1)
(4)〖(x-2)/(x+2)-(x+2)/(x-2)〗×(x^2-2x)/x^2
(5)〖(2/3x)-(2/x+y)【(x+y/3x)-(x-y)】〗÷(x-y)/x
(1)(x^2)/(x+y)-(x+y)/(x+y)
(2)2(a-3)/(a+3)(a-3)-3(a+3)/(a+3)(a-3)+(a+15)/(a+3)(a-3)
(3)1-(a+2)(a-2)/(a-2)(a-1)+(a-1)/(a-2)(a-1)
(4)〖(x-2)/(x+2)-(x+2)/(x-2)〗×(x^2-2x)/x^2
(5)〖(2/3x)-(2/x+y)【(x+y/3x)-(x-y)】〗÷(x-y)/x
(1)(x^2)/(x+y)-(x+y)/(x+y)
=(x^2-x-y)/(x+y)
(2)2(a-3)/(a+3)(a-3)-3(a+3)/(a+3)(a-3)+(a+15)/(a+3)(a-3)
=2/(a+3)-3/(a-3)+(a+15)(a^2-9)
=(2a-6)/(a^2-9)-(3a+9)/(a^2-9)+(a+15)(a^2-9)
=0
(3)1-(a+2)(a-2)/(a-2)(a-1)+(a-1)/(a-2)(a-1)
=1-(a+2)/(a-1)+1/(a-2)
=-3/(a-1)+1/(a-2)
=[-3(a-2)+(a-1)]/(a-1)(a-2)
=(-2a+5)/( a^2-3a+2)
(4)〖(x-2)/(x+2)-(x+2)/(x-2)〗×(x^2-2x)/x^2
=〖(x-2)/(x+2)-(x+2)/(x-2)〗×(x^2-2x)/x^2
=-8x/(x+2)(x-2)×(x-2)/x
=-8/(x+2)
(5)〖(2/3x)-(2/x+y)【(x+y/3x)-(x-y)】〗÷(x-y)/x
=〖(2/3x)-(2/x+y)【(x+y-3x^2+3xy)/3x】〗÷(x-y)/x
=〖(2/3x)-(2/x+y)【(x+y-3x^2+3xy)/3x】〗×x/(x-y)
=2/3(x-y)-(2/x+y)【(x+y-3x^2+3xy)/3(x-y)】
=2/3(x-y)-2(x+y-3x^2+3xy)/3(x^2-y^2)
=[2/3(x+y)-2/3(x+y-3x^2+3xy)]/(x^2-y^2)
=-2x/(x+y)