海唐罗马花园好不好:关于PHP和MYSQL的一个错误

来源:百度文库 编辑:杭州交通信息网 时间:2024/04/19 20:41:06
程序代码部分:
$location_info = mysql_query("SELECT * FROM misc WHERE id='$user_id'");
$location_id = mysql_result($location_info,0,"location_id");

显示错误部分:
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in c:----地址略
不知道是什么原因?

$query = mysql_query("SELECT * FROM misc WHERE id='$user_id'");
$id = mysql_fetch_array($query);
$username = $id['username'];
$userpass = $id['userpass'];