银医生痔疮抗菌凝胶:一道初一题

来源:百度文库 编辑:杭州交通信息网 时间:2024/03/29 17:13:24
已知,X,Y满足4X2+Y2-4X+1+Y+5/4=0.求(X-Y)3
字母后的为次方

题目写错了吧?
4x^2+y^2-4x+1+y+5/4=0
(2x-1)^2+(y+1/2)^2+1=0,这样的x,y在实数范围内不存在。

题目大概应该是:
4x^2+y^2-4x+y+5/4=0
(2x-1)^2+(y+1/2)^2=0,
x=1/2,y=-1/2
(x-y)^3=1

4X2+Y2-4X+1+Y+5/4=0
(2x-1)^2+(y+1/2)^2=0
2x-1=0, y+1/2=0
x=1/2, y=-1/2
(x-y)^3=1

4X2+Y2-4X+1+Y+5/4=0
(2x-1)^2+(y+1/2)^2=0
2x-1=0, y+1/2=0
x=1/2, y=-1/2
(x-y)^3=1