2016年重大会议精神:一道数学题

来源:百度文库 编辑:杭州交通信息网 时间:2024/04/30 00:42:28
计算:
(-xy+1)(xy+1)(x^2 y^2+1)(要步骤)

(-xy+1)(xy+1)(x^2 y^2+1)
= -(xy-1)(xy+1)(x^2y^2+1)
= -(x^2y^2-1)(x^2y^2+1)
= 1-x^4y^4

(1-x^2y^2)(x^2 y^2+1)=1-x^4y^4

(-xy+1)(xy+1)(x^2 y^2+1)
=-(xy-1)(xy+1)(x^2 y^2+1)
=-(x^2 y^2-1^2)(x^2 y^2+1)
=-(x^4y^4-1)
=-x^4y^4+1
=1-x^4y^4

解:原式=(1-xy)(1+xy)(x^2 y^2+1)
=(1-x^2y^2)(1+x^2 y^2)
=1-x^4y^4

注:先观察,发现将原式稍微变下形,然后直接使用平方差公式即可。

(-xy+1)(xy+1)(x^2 y^2+1)
=-(xy-1)(xy+1)(x^2 y^2+1)
=-(x^2 y^2-1^2)(x^2 y^2+1)
=-(x^4y^4-1)
=-x^4y^4+1
=1-x^4y^4

解:原式=(1-xy)(1+xy)(x^2 y^2+1)
=(1-x^2y^2)(1+x^2 y^2)
=1-x^4y^4