杭州交通信息网中国医学科学院整形外科:因式分解
来源：百度文库 编辑：杭州交通信息网 时间：2024/04/30 10:36:24
2(x²+y²)(x+y)²-(x²-y²)²
要有过程，拜托了～！
要有过程，拜托了～！
2(x²+y²)(x+y)²-(x²-y²)²
=2(x²+y²)(x+y)²-[(x+y)(x-y)]²
=2(x²+y²)(x+y)²-(x+y)²(x-y)²
=(x+y)²[2(x²+y²)-(x-y)²]
=(x+y)²[2x²+2y²-x²-y²+2xy]
=(x+y)²[x²+y²+2xy]
=(x+y)²(x+y)²
=[(x+y)]的4次方----啊，“4次方”我打不出来！
原式=2(x²+y²)(x+y)²-[(x+y)(x-y)]²
=2(x²+y²)(x+y)²-(x-y)²(x+y)²
=(2x²+2y²-x²-y²+2xy)(x+y)²
=(x+y)^4
上面的两位....不说你们什么了.....尤其顶楼的...
(x+y)2[2x2+2y2-x2-y2+2xy]=(x+y)4
在后头的数字是几次方，
你这个小孩，这么EZ的题都不会，说你什么好
2(x²+y²)(x+y)² -（x²-y²)(x+y)²
=(x+y)²[2(x²+y²)-（x²-y²)]
=(x+y)²(x+y)²
=(x+y)4
=2(x^2+y^2)(x+y)^2-(x+y)^2(x-y)^2
=(x+y)^2[2(x^2+y^2)-(x-y)^2]
=(x+y)^2*(x+y)^2
=(x+y)^4
2(x²+y²)(x+y)²-(x²-y²)²
=2(x²+y²)(x²+2xy+y²)-(x²*x²-2*x²*y²+y²*y²)
=2(x²*x²+2*x²*x*y+x²*y²+x²*y²+2*x*y*y²+y²*y²)-(x²*x²-2*x²*y²+y²*y²)
=x²*x²+4*x*y*x²+6*x²*y²+4*x*y*y²+y²*y²）
=（x+y）*（x+y）*（x+y）*（x+y）